Change a certain string of an automatically printed number in swift 4
I wanted to copy this page http://www.99-bottles-of-beer.net/lyrics.html in IOS playground to practice but I would like to ask a question and I hope for your help. I created a function called vantanoveBottles, created a variable "texts" of type String and used "for and in" for numbers from 0 ... 5 I created a string constancy in which I entered numbers and text and then I added texts + newLine as in the code.Now if you compare the site when it comes to 1 and says that there are no more beers do not use the number 0, instead I get out so I would basically print example numbers from 1 to 98 inverse with string of text, (and I did this) then come to 1 should not go out "1 bottles of beer on the wall, 1 bottles of beer. n" Take one down and pass it around, 0 bottles of beer on the wall. " the 0 must be eliminated must not go out, how do I do? This is a test code
func novantanoveBottles () ->String {
var testi: String = ""
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around, (numeri - 1) bottles of beer on the wall. n"
testi += newLine
}
testi += "n n n No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall."
return testi
}
print(novantanoveBottles())
ios swift4
asked Nov 19 at 11:36
Michele Russo
31
add a comment |
I wanted to copy this page http://www.99-bottles-of-beer.net/lyrics.html in IOS playground to practice but I would like to ask a question and I hope for your help. I created a function called vantanoveBottles, created a variable "texts" of type String and used "for and in" for numbers from 0 ... 5 I created a string constancy in which I entered numbers and text and then I added texts + newLine as in the code.Now if you compare the site when it comes to 1 and says that there are no more beers do not use the number 0, instead I get out so I would basically print example numbers from 1 to 98 inverse with string of text, (and I did this) then come to 1 should not go out "1 bottles of beer on the wall, 1 bottles of beer. n" Take one down and pass it around, 0 bottles of beer on the wall. " the 0 must be eliminated must not go out, how do I do? This is a test code
func novantanoveBottles () ->String {
var testi: String = ""
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around, (numeri - 1) bottles of beer on the wall. n"
testi += newLine
}
testi += "n n n No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall."
return testi
}
print(novantanoveBottles())
ios swift4
asked Nov 19 at 11:36
Michele Russo
31
Whats the issue? Looks alright to me
– Scriptable
Nov 19 at 11:40
if you are comparing the page, in last when it comes to "1 bottle of beer on the wall, 1 bottle of beer. "Do not print the number 0 instead I print it, how can I do to delete the 0 also me?
– Michele Russo
Nov 19 at 11:43
I think I understand what you mean.. check my answer below
– Scriptable
Nov 19 at 11:45
add a comment |
I wanted to copy this page http://www.99-bottles-of-beer.net/lyrics.html in IOS playground to practice but I would like to ask a question and I hope for your help. I created a function called vantanoveBottles, created a variable "texts" of type String and used "for and in" for numbers from 0 ... 5 I created a string constancy in which I entered numbers and text and then I added texts + newLine as in the code.Now if you compare the site when it comes to 1 and says that there are no more beers do not use the number 0, instead I get out so I would basically print example numbers from 1 to 98 inverse with string of text, (and I did this) then come to 1 should not go out "1 bottles of beer on the wall, 1 bottles of beer. n" Take one down and pass it around, 0 bottles of beer on the wall. " the 0 must be eliminated must not go out, how do I do? This is a test code
func novantanoveBottles () ->String {
var testi: String = ""
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around, (numeri - 1) bottles of beer on the wall. n"
testi += newLine
}
testi += "n n n No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall."
return testi
}
print(novantanoveBottles())
ios swift4
asked Nov 19 at 11:36
Michele Russo
31
I wanted to copy this page http://www.99-bottles-of-beer.net/lyrics.html in IOS playground to practice but I would like to ask a question and I hope for your help. I created a function called vantanoveBottles, created a variable "texts" of type String and used "for and in" for numbers from 0 ... 5 I created a string constancy in which I entered numbers and text and then I added texts + newLine as in the code.Now if you compare the site when it comes to 1 and says that there are no more beers do not use the number 0, instead I get out so I would basically print example numbers from 1 to 98 inverse with string of text, (and I did this) then come to 1 should not go out "1 bottles of beer on the wall, 1 bottles of beer. n" Take one down and pass it around, 0 bottles of beer on the wall. " the 0 must be eliminated must not go out, how do I do? This is a test code
func novantanoveBottles () ->String {
var testi: String = ""
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around, (numeri - 1) bottles of beer on the wall. n"
testi += newLine
}
testi += "n n n No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall."
return testi
}
print(novantanoveBottles())
ios swift4
ios swift4
asked Nov 19 at 11:36
Michele Russo
31
asked Nov 19 at 11:36
Michele Russo
31
asked Nov 19 at 11:36
Michele Russo
31
asked Nov 19 at 11:36
Michele Russo
31
asked Nov 19 at 11:36
Michele Russo
31
31
Whats the issue? Looks alright to me
– Scriptable
Nov 19 at 11:40
if you are comparing the page, in last when it comes to "1 bottle of beer on the wall, 1 bottle of beer. "Do not print the number 0 instead I print it, how can I do to delete the 0 also me?
– Michele Russo
Nov 19 at 11:43
I think I understand what you mean.. check my answer below
– Scriptable
Nov 19 at 11:45
add a comment |
Whats the issue? Looks alright to me
– Scriptable
Nov 19 at 11:40
if you are comparing the page, in last when it comes to "1 bottle of beer on the wall, 1 bottle of beer. "Do not print the number 0 instead I print it, how can I do to delete the 0 also me?
– Michele Russo
Nov 19 at 11:43
I think I understand what you mean.. check my answer below
– Scriptable
Nov 19 at 11:45
Whats the issue? Looks alright to me
– Scriptable
Nov 19 at 11:40
Whats the issue? Looks alright to me
– Scriptable
Nov 19 at 11:40
if you are comparing the page, in last when it comes to "1 bottle of beer on the wall, 1 bottle of beer. "Do not print the number 0 instead I print it, how can I do to delete the 0 also me?
– Michele Russo
Nov 19 at 11:43
if you are comparing the page, in last when it comes to "1 bottle of beer on the wall, 1 bottle of beer. "Do not print the number 0 instead I print it, how can I do to delete the 0 also me?
– Michele Russo
Nov 19 at 11:43
I think I understand what you mean.. check my answer below
– Scriptable
Nov 19 at 11:45
I think I understand what you mean.. check my answer below
– Scriptable
Nov 19 at 11:45
add a comment |
1 Answer
1
active
oldest
votes
You can just add a check before you add that part of the text
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around"
if numeri != 1 {
test1 += ", (numeri - 1) bottles of beer on the wall. n
} else {
test1 += ".n"
}
testi += newLine
}
answered Nov 19 at 11:45
Scriptable
12.4k43253
I always print the 0 in the playground
– Michele Russo
Nov 19 at 11:54
oh okay I solved thanks a lot of your answer :)
– Michele Russo
Nov 19 at 11:56
glad to of helped, good luck with the project
– Scriptable
Nov 19 at 12:34
add a comment |
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1 Answer
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active
oldest
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
You can just add a check before you add that part of the text
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around"
if numeri != 1 {
test1 += ", (numeri - 1) bottles of beer on the wall. n
} else {
test1 += ".n"
}
testi += newLine
}
answered Nov 19 at 11:45
Scriptable
12.4k43253
I always print the 0 in the playground
– Michele Russo
Nov 19 at 11:54
oh okay I solved thanks a lot of your answer :)
– Michele Russo
Nov 19 at 11:56
glad to of helped, good luck with the project
– Scriptable
Nov 19 at 12:34
add a comment |
You can just add a check before you add that part of the text
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around"
if numeri != 1 {
test1 += ", (numeri - 1) bottles of beer on the wall. n
} else {
test1 += ".n"
}
testi += newLine
}
answered Nov 19 at 11:45
Scriptable
12.4k43253
I always print the 0 in the playground
– Michele Russo
Nov 19 at 11:54
oh okay I solved thanks a lot of your answer :)
– Michele Russo
Nov 19 at 11:56
glad to of helped, good luck with the project
– Scriptable
Nov 19 at 12:34
add a comment |
You can just add a check before you add that part of the text
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around"
if numeri != 1 {
test1 += ", (numeri - 1) bottles of beer on the wall. n
} else {
test1 += ".n"
}
testi += newLine
}
answered Nov 19 at 11:45
Scriptable
12.4k43253
You can just add a check before you add that part of the text
for numeri in (1...99).reversed() {
let newLine:String = "n (numeri) bottles of beer on the wall, (numeri) bottles of beer.n Take one down and pass it around"
if numeri != 1 {
test1 += ", (numeri - 1) bottles of beer on the wall. n
} else {
test1 += ".n"
}
testi += newLine
}
answered Nov 19 at 11:45
Scriptable
12.4k43253
answered Nov 19 at 11:45
Scriptable
12.4k43253
answered Nov 19 at 11:45
Scriptable
12.4k43253
answered Nov 19 at 11:45
Scriptable
12.4k43253
12.4k43253
I always print the 0 in the playground
– Michele Russo
Nov 19 at 11:54
oh okay I solved thanks a lot of your answer :)
– Michele Russo
Nov 19 at 11:56
glad to of helped, good luck with the project
– Scriptable
Nov 19 at 12:34
add a comment |
I always print the 0 in the playground
– Michele Russo
Nov 19 at 11:54
oh okay I solved thanks a lot of your answer :)
– Michele Russo
Nov 19 at 11:56
glad to of helped, good luck with the project
– Scriptable
Nov 19 at 12:34
I always print the 0 in the playground
– Michele Russo
Nov 19 at 11:54
I always print the 0 in the playground
– Michele Russo
Nov 19 at 11:54
oh okay I solved thanks a lot of your answer :)
– Michele Russo
Nov 19 at 11:56
oh okay I solved thanks a lot of your answer :)
– Michele Russo
Nov 19 at 11:56
glad to of helped, good luck with the project
– Scriptable
Nov 19 at 12:34
glad to of helped, good luck with the project
– Scriptable
Nov 19 at 12:34
add a comment |
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Whats the issue? Looks alright to me
– Scriptable
Nov 19 at 11:40
if you are comparing the page, in last when it comes to "1 bottle of beer on the wall, 1 bottle of beer. "Do not print the number 0 instead I print it, how can I do to delete the 0 also me?
– Michele Russo
Nov 19 at 11:43
I think I understand what you mean.. check my answer below
– Scriptable
Nov 19 at 11:45